If the effective current is 3.5 A, what is the peak-to-peak value of the applied AC current?

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Multiple Choice

If the effective current is 3.5 A, what is the peak-to-peak value of the applied AC current?

Explanation:
RMS (effective) current is 3.5 A, and for a sinusoidal AC, the peak value is Ipeak = Irms × sqrt(2) ≈ 3.5 × 1.414 ≈ 4.95 A. The peak-to-peak current is twice the peak value, so Ipp ≈ 2 × 4.95 ≈ 9.9 A. Therefore the peak-to-peak value is about 9.9 A.

RMS (effective) current is 3.5 A, and for a sinusoidal AC, the peak value is Ipeak = Irms × sqrt(2) ≈ 3.5 × 1.414 ≈ 4.95 A. The peak-to-peak current is twice the peak value, so Ipp ≈ 2 × 4.95 ≈ 9.9 A. Therefore the peak-to-peak value is about 9.9 A.

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